I did two runs on the same page with the same characters. I guess I have a question. Every one else commenting seems to have way more on their page, I think I'm missing something. Is there more to the rolling than just rolling 5 times, plus one for the variable in the ending? Either way I found it fun.
Thank you for checking out my game! 💚
As for your question, there are a couple of elements. Some players write big, some write small. The paper size can also make it seem like it is more filled, when in reality it's just a smaller canvas space. There is also a bit of randomness. It's true that a standard ending could be gotten with 5-6 very lucky rolls, but that's not the luckiest roll there is. I've known at least one player who got 6-6-6 on the first try, effectively ending the game in 3 rolls. (that's a 1 in 216 chance, not quite shiny pokemon odds but still pretty rare 😅)
I think I may have confused myself more -_-. WAIT I think I figured it out. For my own clarification, I roll a 4, do the 4 square. If my second roll is a different number, do that single number square. The next time I get a 4, I do 44, and so on and so forth. Is that correct? So I would have to roll five 4's to get the 4 column ending, but I am also continuing down the other columns as I roll those numbers. That makes so much more sense than what I was doing. I should play this again and play correctly this time.
Thank you!