How would hard mode logic work in dordle?
Let's work an example. Suppose (3 letter words to keep it simple) the secret words are DOG and CAT. Suppose your first guess is COD, which gets played on both sides. On the left side (the DOG side), O gets a green and D gets a yellow. On the right side (the CAT side), C gets a green. So now what words are allowed? Must you have C first (since it got a green on the right) and O second (since it got a green on the left)? Must it have a D somewhere in it, since D got a yellow? If all of those are required then you're stuck playing COD again and can never solve the puzzle. If only some are required, then you can only ever solve one side. Is there different logic that makes it work? I'm not sure there is.