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I'm a little confused on one point. The Spymaster needs two cards if matching suit to play an obstacle. What if they have cards left, but no matching pairs?
Hello, the rule is written as follows:
"When the spymaster reveals an obstacle to the spies they will play 1-2 card(s) from their hand of a matching suit."
This means the spymaster has two options when revealing an obstacle:
1 - Play a 1 card, which will only have one suit and one difficulty value.
2 - Play 2 cards, which must have the same suit to determine the challenge type and a difficulty value that will be the sum of the card's value.
I hope this clears up any confusion.
Oh, that makes sense. I must have missed that.
Cool game!
Comments
I'm a little confused on one point. The Spymaster needs two cards if matching suit to play an obstacle. What if they have cards left, but no matching pairs?
Hello, the rule is written as follows:
"When the spymaster reveals an obstacle to the spies they will play 1-2 card(s) from their hand of a matching suit."
This means the spymaster has two options when revealing an obstacle:
1 - Play a 1 card, which will only have one suit and one difficulty value.
2 - Play 2 cards, which must have the same suit to determine the challenge type and a difficulty value that will be the sum of the card's value.
I hope this clears up any confusion.
Oh, that makes sense. I must have missed that.
Cool game!